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X′(t)=[2−51−2]X+[−costsint]
Eigenvalues: λ∈{−i,i}
Xh(t)=c1(v→1cost−v→2sint)+c2(v→2cost+v→1sint)
Guess for Xp(t):
X′(t)=[0110]X+[t−1]X(0)=[21]
{ℒ{x′}=ℒ{y}+ℒ{t}ℒ{y′}=ℒ{x}+ℒ{−1}
{sℒ{x}−x(0)=ℒ{y}+1s2sℒ{y}−y(0)=ℒ{x}+1s
{sℒ{x}−2=ℒ{y}+1s2sℒ{y}−1=ℒ{x}+1s
ℒ{x}=sℒ{y}−1+1s
ℒ{y}=1s2(s2−1)+1s2−1+ss2−1
ℒ{x}=s(1s2(s2−1)+1s2−1+ss2−1)−1+1s
Take inverse Laplace transforms
Using matrix notation,
X′(t)=[2−13−2]X(t)+[1−1]etX(0)=[30]
ℒ{X′}=[2−13−2]ℒ{X}+[1,−1]ℒ{et}sℒ{X}−X(0)=[2−13−2]ℒ{X}+[1−1](1s−1)(sI−[2−13−2])ℒ{X}=X(0)+1s−1[1−1]ℒ{X}=[s−21−3s+2]−1(X(0)+1s−1[1−1])ℒ{X}=1s2−1[s+2−13s−2][3+1s−1−1s−1]