MATH 308 Lecture 23

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End Exam 2 content
Lecture Notes


Exam Review

Fundamental Sets of Solutions

Recall that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_1} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_2} are a fundamental set of solutions if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle W(y_1, y_2) \ne 0} .

Reduction of Order

Given a differential equation and one solution Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_1} , we want to find a second solution in the form Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_2 = y_1 \, \lambda}

For example, given Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (x-1)\,y'' - x\,y' + y = 0} and solution Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_1 = \mathrm{e}^{x}} , we find the second solution as follows:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align} y_2 &= \lambda \, \mathrm{e}^{x} \\ y_2' &= \lambda' \, \mathrm{e}^{x} + \lambda \, \mathrm{e}^{x} \\ y_2'' &= \lambda'' \, \mathrm{e}^{x} + 2 \lambda' \, \mathrm{e}^{x} + \lambda \, \mathrm{e}^{x} \\ 0 &= (x-1) \, \left( \lambda'' + 2 \lambda' + \lambda \right) \, \mathrm{e}^{x} - x\,(\lambda + \lambda')\,\mathrm{e}^{x} + \lambda \, \mathrm{e}^{x} \\ 0 &= (x-1) \, \lambda'' + (x-2)\, \lambda' + \cancel{0 \lambda} \\ \mu &= \mathrm{e}^{\int \frac{x-2}{x-1} \, \mathrm{d}x} = \mathrm{e}^{\int 1 - \frac{1}{x-1} \, \mathrm{d}x} = \frac{\mathrm{e}^{x}}{x-1} \\ \frac{\mathrm{d}}{\mathrm{d}x} \left( \lambda' \, \frac{\mathrm{e}^{x}}{x-1} \right) &= 0 \\ \lambda' \, \frac{\mathrm{e}^{x}}{x-1} &= C \\ \lambda' &= C \, (x-1) \, \mathrm{e}^{-x} \\ \lambda &= -C \, ((x+1) \, \mathrm{e}^{-x} - \mathrm{e}^{-x}) \end{align}}


Variation of Parameters

Recall that for non-homogeneous differential equations, a particular solution may be found by solving for the homogeneous solution, and then using the corresponding Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_1} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle y_2} in the formulae:

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align} c_1 &= -\int_{x_0}^x \frac{y_2 \, g}{W(y_1,y_2)} \, \mathrm{d}x \\ c_2 &= \int_{x_0}^x \frac{y_1 \, g}{W(y_1,y_2)} \, \mathrm{d}x \end{align}}

Laplace Transforms

Review starting with MATH 308 Lecture 17.