MATH 415 Lecture 2

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Section 3: Isomorphic Binary Structures

A binary structure consits of a set S and a binary operation *.

Tables from the book define binary structures:

  • S1={a,b,c}, *, *^, *~
  • S2={#,$,&}, *′
  • S3={x,y,z}, *″

(ith row and jth column represent si*sj for si,sj∈S)

Table 3.1
* a b c
a c a b
b a b c
c b c a
Table 3.2
*′ # $ &
# & # $
$ # $ &
& $ & #
Table 3.3
*″ x y z
x x y z
y y z x
z z x y
Table 3.4
*″ y x z
y z y x
x y x z
z x z y
Table 3.5
*~ a b c
a b b b
b b b b
c b b b
Table 3.6
*^ a b c
a c a b
b b c a
c a b c


Tables 3.1 and 3.2 are bijections of each other with the following transformation:

  • a ↔ #
  • b ↔ $
  • c ↔ &

Table 3.6 is reflexive

Definition

Let (S,*) and (S′,*′) be binary algebraic structures. An isomorphism of S with S′ is a one-to-one [1] function ϕ mapping S onto [2] S′ such that ϕ(x*y)=ϕ(x)*′ϕ(y) for all x,y∈S.

Notation: (S,*)≃(S′,*′)

Since ϕ is both one-to-one and onto, we call it a bijection.

Note: A function that is not a bijection but still satisfies the property ϕ(x*y)=ϕ(x)*′ϕ(y) is called a homomorphism. In other words, an isomorphism is a bijective homomorphism

Recall isomorphic structures from yesterday:

  • ⟨Un,⋅⟩≃⟨ℤn,+n⟩
  • ⟨U,⋅⟩≃⟨ℝ2π,+2π⟩≃⟨ℝc,+c⟩


Showing Non-Isomorphism

Keep word invariant in mind...

Examples

Addition and Multiplication

⟨ℝ,+⟩≃⟨ℝ+,⋅⟩

Transformation function is ϕ=ex: it is a bijection because

  • (one-to-one) monotonically increasing
  • (onto) ∀z>0∃tet=z

It is homomorphic because ex+y=ex⋅ey

It also has an inverse mapping ϕ−1=ln⁡y


Integers and Even Integers

⟨ℤ,+⟩≃⟨2ℤ,+⟩

ϕ:m→2m

Easy to see bijection homomorphism: ϕ(m+k)=2(m+k)=2m+2k=ϕ(m)+ϕ(k)

ℤ and ℤ+ have same cardinality (both countable), but

⟨ℤ,⋅⟩≄⟨ℤ+,⋅⟩

Assume we have a homomorphic function ϕ(mn)=ϕ(m)⋅ϕ(n), then this would satisfy equation x⋅x=x. There are two solutions in ℤ, namely 0 and 1, but only one solution in ℤ+, namely 1. This is a contradiction.


Identity

Given a binary structure ⟨S,*⟩, we call e∈S an identity for * if e*s=s*e=s for all s∈S

  • 1 is identity for multiplication
  • 0 is identity for addition

Theorem 3.13

Uniqueness of Identity Element

A binary structure has at most one identity element.

Proof by contradiction. Assume we have two distinct identities e1,e2∈S for *. Then e1*e2=e2 and e1*e2=e1. By transitivity, e2=e1. Contradiction.


Groups

A group (G,*) has the following axioms:

  1. * is associative
  2. There is an identity element e∈G
  3. Corresponding to each a∈G, there is an "inverse" element a−1 such that a*a′=a−1*a=e


Group ⟨G,*⟩ is abelian [3] (or commutative) if * is commutative. That is, a*b=b*a for all a,b∈G.

Examples

⟨U,⋅⟩ is a group:

  1. multiplication is associative
  2. identity element is 1
  3. inverse of z=eiθ is z−1=e−iθ.
  • ⟨ℤ,+⟩ is an abelian group
  • ⟨ℚ,+⟩ is an abelian group
  • ⟨ℝ,+⟩ is an abelian group
  • ⟨ℤ+,⋅⟩ is not a group because there is no inverse for 2
  • ⟨Mn(ℝ),⋅⟩ is not a group since not all matrices are invertible, however
  • ⟨Mn⋅(ℝ),⋅⟩ (where Mn⋅(ℝ) is the set of invertible matrices of size n) is a group


Footnotes

  1. ↑ a function is one-to-one if all elements of domain have unique image in codomain
  2. ↑ a function is onto if the range (i.e. set of all images of function) is equivalent to codomain
  3. ↑ The name "abelian" is from the great mathematician Abel.