MATH 323 Lecture 6

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Elementary Matrices

System of equations Ax→=b→ can be converted to Ux→=c→, where U=(∏i=k1Ei)A and c→=(∏i=k1Ei)b→. Ei is an elementary matrix of type 1, 2, or 3.

Properties:

  • Premultiplication performs rule operations on rows
  • Postmultiplication performs rule operations on columns
  • E−1 is an elementary matrix of the same type.

Row Equivalence

describes that a matrix A can be converted to another matrix B by applying elementary matrices: B=(∏i=k1Ei)A

If A is nonsingular, then A is row equivalent to I: I=(∏i=k1Ei)A=AA−1A−1=∏i=k1Ei

Therefore, the augmented matrix [AI] can be converted to [IA−1] by performing elementary row operations to convert it to reduced row echelon form.

Example:

[143100−1−20010223001]→[100−12−121201014−14−14001161216]A=[143−1−20223]A−1=[−12−121214−14−14161216]

Therefore, if we have the system of equations Ax→=b→, the solution is x→=A−1b→.

Triangular Matrices

Suppose A is a n×n square matrix.

  • If A is of the form (x10…00⋱0⋮⋮0⋱00…0xn), it is diagonal.
  • If A is of the form (x1α2…β0⋱0⋮⋮0⋱γδ00xn), it is upper triangular.
  • If A is of the form (x10…0α⋱0⋮⋮β⋱0γ…δxn), it is lower triangular.

Triangular Factorization

If a n×n matrix A can be reduced to strict upper triangular form using row operations of type 3, then A=∠U, where ∠ – unit lower triangular matrix and U – strictly upper triangular matrix.

Each operation is of the form (#)−ℓij(#), where i and j are row indices of A.

A=[242152419]⟶U=[242031008]

ℓ21=12, ℓ31=2, and ℓ32=−3.

If we construct a n×n matrix by replacing elements of In with corresponding ℓ values, we get L=[100−12102−31] such that A=LU and L=∏i=k1Ei−1, where Ei−1 is a single ℓ replacement in I for each step.

Determinants

For a n×n square matrix A, there is a corresponding scalar determinant of A

Written in any of the following formats:

det⁡(A)=|A|=|a11…a1n⋮⋱⋮an1…ann|

A matrix is singular iff its determinant is 0.

  1. For a 1×1 square matrix, |A|=a
  2. For a 2×2 square matrix, |A|=a11a22−a12a21 (product of main diagonal minus product of "secondary diagonal")
  3. For a 3×3 square matrix, |A|=a11|a22a23a32a33|−a22|a21a23a31a33|+a13|a21a22a31a32| (See MATH 251 Lecture 10 for hints and tricks)