MATH 323 Lecture 17

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Linear Transformation

∀L:ℝn→ℝm∃A∈ℝm×n

A=(a→i=L(e→i)

Rotation Transformation

Let L be a rotation by angle θ about the origin.

L(e→1)=(cos⁡θsin⁡θ)L(e→2)=(−sin⁡θcos⁡θ)A=(cos⁡θ−sin⁡θsin⁡θcos⁡θ)

In General

For arbitrary L:V→W, where E=[v1,…,vn] is a basis in V and F=[w1,…,wm] is a basis in W.

v→[v]E∈ℝn is the coordinate vector of v w.r.t E so v=∑i=1nxivi=⟨x1,…,xn⟩

For some ∑i=1myiwi=L(v)∈W, we can represent [L(v)]F as ⟨y1,…,ym⟩∈ℝm.

y→=Ax→⟺[L(v)]F=A[v]E [1], so what is A?

a→j=[L(vj)]F for j=1,…,n
A=(a→i,…,a→n)

Theorem 4.2.2

Matrix representation theorem

If E=[v1,…,vn] and F=[w1,…,wm] are ordered bases for vector spaces V and W respectively, then corresponding to each linear transformation L:V→W there is an m×n matrix A such that

[L(v)]F=A[v]E for each v∈V

A is the matrix representing L relative to the ordered bases E and F.

In fact, A=(a→1,…,a→n), where a→j=[L(vj)]F for j=1,…,n.

Examples

For x→∈ℝ3 and [b→1=⟨1,1⟩,b→2=⟨−1,1⟩] is a basis in ℝ2, find the matrix A representing L(x→)=x1b→1+(x2+x3)b→2 w.r.t. ordered bases [e→1,e→2,e→3] (standard 3D basis) to B=[b→1,b→2]

Just take A=(aj=L(e→i))=(100011)


L(αb→1+βb→2)=(α+β)b→1+2βb→2, where [b→1,b→2] is a basis for ℝ2. Find A.

A=(L(1⋅b→1+0⋅b→2),L(0⋅b→1+1⋅b→2))=(1102)


D:P3→P2, where D(p(x))=p′(x).

[x2,x,1] forms basis for P3, and [x,1] forms basis for P2

D(x2)=2x=2⋅x+0⋅1D(x)=1=0⋅x+1⋅1D(1)=0=0⋅x+0⋅1D(ax2+bx+c)=2ax+b

Thus A=[200010]

[p(x)][x2,x,1]=⟨a,b,c⟩[D(p(x))][x,1]=⟨2a,b⟩


Reversing Linear Transformations

Theorem 4.2.3

Given E=[u→1,…u→n] and F=[b→1,…,b→m] are bases for ℝn and ℝm respectively,

If A is the matrix representing L:ℝn→ℝm w.r.t. E and F, then

a→j=B−1L(u→j) for j=1,…,n, where B=(b→1,…,b→m)

Corollary 4.2.4

If A is the matrix representing the linear transformation L:ℝn→ℝm w.r.t. E and F, then the rref of (b→1,…,b→m∣L(u→1),…,L(u→n)) is (I∣A).

Example

L:ℝ2→ℝ3,

Basis [u→1,u→2] is u→1=⟨1,2⟩, u2=⟨3,1⟩

Basis [b→1,b→2,b→3] is b→1=⟨1,0,0⟩, b→2=⟨1,1,0⟩, b→3=⟨1,1,1⟩

L(x→)=(x2x1+x2x1−x2)

What is A w.r.t. [u→1,u→2] and [b→1,b→2,b→3]?

L(u→1)=⟨2,3,−1⟩L(u→2)=⟨1,4,2⟩

[1112101134001−12]⟶[100−1−301042001−12]

A=(−1−342−12)

Footnotes

  1. ↑ The correspondence between V and ℝn given by (x→∈ℝn)=[v∈V]E; and between w=L(v)∈W and Ax→=[w]F∈ℝm is called isomorphism